35b^2-41b=24

Solution for 35b^2-41b=24 equation:

35b^2-41b=24

We move all terms to the left:

35b^2-41b-(24)=0

a = 35; b = -41; c = -24;
Δ = b2-4ac
Δ = -412-4·35·(-24)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-71}{2*35}=\frac{-30}{70}
=-3/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+71}{2*35}=\frac{112}{70}
=1+3/5
$